JEE Main 2021 · ChemistryMultiple choiceDiagram basedMediumApplication
JEE Main 18 March 2021, Shift 2, Chemistry Q46
Question 46 of 90 in this shift, Chemistry question 16 of 30, Section A.
[figure: reaction scheme] Consider the above reaction, the product ‘X’ and ‘Y’ respectively are :
The figure, in words
Reaction drawn: 2 [five-membered ring ketone, C=O at top], arrow labelled dil NaOH, product “X”, arrow labelled H+, Heat, product “Y”. Each option shows two drawn structures separated by a comma.- (1)[figure: X = five-membered ring ketone (C=O at top) whose carbon next to C=O is single bonded to a carbon of a second five-membered saturated ring, that carbon also bearing OH; Y = five-membered ring ketone whose carbon next to C=O is single bonded to a carbon of a second five-membered ring that has one C=C in the ring at the attached carbon]
- (2)[figure: X = five-membered saturated ring bearing OH on one carbon, single bonded at the adjacent carbon to a carbon next to the C=O of a second five-membered ring ketone; Y = five-membered ring ketone whose carbon next to C=O is single bonded to a carbon of a second five-membered ring that has one C=C in the ring at the attached carbon]
- (3)[figure: X = five-membered ring ketone (C=O at top) whose carbon next to C=O is single bonded to a carbon of a second five-membered saturated ring, that carbon also bearing OH; Y = five-membered ring ketone whose carbon next to C=O is joined by a C=C double bond (exocyclic) to a carbon of a second five-membered ring that also has one C=C in the ring]
- (4)[figure: X = five-membered ring ketone (C=O at top) whose carbon next to C=O is single bonded to a carbon of a second five-membered saturated ring, that carbon also bearing OH; Y = five-membered ring ketone whose carbon next to C=O is joined by a C=C double bond (exocyclic) to a carbon of a second five-membered saturated ring]Official answer
Official answer
Option 4
NTA final key.
- Topic
- Aldol and Cannizzaro
- Idea tested
- Self-Aldol Condensation