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Saturday, 31 October

JEE Main 2021 · PhysicsMultiple choiceDiagram basedMediumData or graph

JEE Main 18 March 2021, Shift 2, Physics Q3

Question 3 of 90 in this shift, Physics question 3 of 30, Section A.

A particle of mass m moves in a circular orbit under the central potential field, U(r)=−CrU(r) = -\frac{C}{r}, where C is a positive constant. The correct radius –velocity graph of the particle’s motion is :

The figure, in words

All four options are graphs of r (vertical axis) against v (horizontal axis), origin labelled O.
  1. (1)[figure: graph of r (vertical) vs v (horizontal) with origin O; curve starts at the origin tangent to the v axis and rises with increasing steepness toward the upper right]
  2. (2)[figure: graph of r vs v; straight line from the origin rising to the upper right]
  3. (3)[figure: graph of r vs v; decreasing curve starting high near the r axis and flattening toward the v axis as v increases, not touching the origin]Official answer
  4. (4)[figure: graph of r vs v; curve starting at a point on the r axis, bending downward like a quarter circle arc and ending on the v axis]

Official answer

Option 3

NTA final key.

Idea tested
Orbital Velocity