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Friday, 9 October

JEE Main 2021 · ChemistryNumerical answerNumerical valueMediumMulti-step

JEE Main 18 March 2021, Shift 1, Chemistry Q60

Question 60 of 90 in this shift, Chemistry question 30 of 30, Section B.

A reaction of 0.1 mole of Benzylamine with bromomethane gave 23 g of Benzyl trimethyl ammonium bromide. The number of moles of bromomethane consumed in this reaction are n×10−1n\times10^{-1}, when n=n = __________. (Round off to the Nearest Integer). [Given : Atomic masses : C : 12.0 u, H : 1.0 u, N : 14.0 u, Br : 80.0 u]

Official answer

3

NTA final key.

Chapter
Amines
Topic
Amines