JEE Main 2021 · PhysicsNumerical answerNumerical valueMediumCalculation

JEE Main 18 March 2021, Shift 1, Physics Q21

Question 21 of 90 in this shift, Physics question 21 of 30, Section B.

An npn transistor operates as a common emitter amplifier with a power gain of

10^6

. The input circuit resistance is 100

\Omega

and the output load resistance is 10 k

\Omega

. The common emitter current gain '

\beta

' will be __________. (Round off to the Nearest Integer)

Official answer

100

NTA final key.

Chapter: Semiconductor Electronics: Materials, Devices and Simple Circuits
Topic: Transistors
Idea tested: CE Amplifier Voltage Gain

Same idea in other shifts

Asked 3× in all

8 Apr 2023, Shift 2 · Q43For a given transistor amplifier circuit in CE configuration $V_{CC} = 1$ V, $R_C = 1$ k $\Omega$ , $R_b = 100$ k $\Omega$ and $\beta = 100$ .…EasySingle correctHas a figure
24 Jun 2022, Shift 1 · Q53A transistor is used in common-emitter mode in an amplifier circuit. When a signal of 10 mV is added to the base-emitter voltage, the base…EasyNumerical value

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 42 of the 174 JEE Main shifts held from 2017 to 2026.