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Saturday, 31 October

JEE Main 2021 · ChemistryNumerical answerNumerical valueMediumCalculation

JEE Main 17 March 2021, Shift 1, Chemistry Q55

Question 55 of 90 in this shift, Chemistry question 25 of 30, Section B.

The oxygen dissolved in water exerts a partial pressure of 20 kPa in the vapour above water. The molar solubility of oxygen in water is __________ ×10−5 mol dm−3\times 10^{-5}\ \mathrm{mol\ dm^{-3}}. (Round off to the Nearest Integer). [Given : Henry’s law constant =KH=8.0×104= K_H = 8.0 \times 10^4 kPa for O2\mathrm{O_2}. Density of water with dissolved oxygen =1.0 kg dm−3= 1.0\ \mathrm{kg\ dm^{-3}}]

Official answer

25

NTA final key.

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Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 108 of the 174 JEE Main shifts held from 2017 to 2026.