JEE Main 2021 · PhysicsNumerical answerNumerical valueMediumCalculation

JEE Main 16 March 2021, Shift 2, Physics Q21

Question 21 of 90 in this shift, Physics question 21 of 30, Section B.

If one wants to remove all the mass of the earth to infinity in order to break it up completely. The amount of energy that needs to be supplied will be

\frac{x}{5}\frac{GM^2}{R}

where

x

is ________. (Round off to the Nearest Integer) (M is the mass of earth, R is the radius of earth, G is the gravitational constant)

Official answer

NTA final key.

Chapter: Gravitation
Topic: Gravitational Potential
Idea tested: Gravitational Binding Energy

Same topic in other shifts

All Gravitational Potential questions

2 Apr 2026, Shift 2 · Q31If a body of mass 1 kg falls on the earth from infinity, it attains velocity (v) and kinetic energy (k) on reaching the surface of earth.…MediumSingle correct
5 Apr 2026, Shift 2 · Q32A body of mass $m$ is taken from the surface of earth to a height equal to twice the radius of earth ( $R_e$ ). The increase in potential…EasySingle correct
4 Apr 2025, Shift 2 · Q29An object is kept at rest at a distance of 3R above the earth's surface where R is earth's radius. The minimum speed with which it must be…MediumSingle correct
6 Sep 2020, Shift 2 · Q6Two planets have masses M and 16 M and their radii are a and 2a, respectively. The separation between the centres of the planets is 10a. A…HardSingle correct

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 42 of the 174 JEE Main shifts held from 2017 to 2026.