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Saturday, 31 October

JEE Main 2021 · PhysicsNumerical answerNumerical valueEasyCalculation

JEE Main 25 July 2021, Shift 2, Physics Q28

Question 28 of 90 in this shift, Physics question 28 of 30, Section B.

From the given data, the amount of energy required to break the nucleus of aluminium 1327Al^{27}_{13}\mathrm{Al} is __________ x×10−3x\times10^{-3} J. Mass of neutron=1.00866 u Mass of proton=1.00726 u Mass of Aluminium nucleus=27.18846 u (Assume 1 u corresponds to xx J of energy) (Round off to the nearest integer)

Official answer

27

NTA final key.

Chapter
Nuclei
Topic
Nuclear Binding Energy
Idea tested
Total Binding Energy

Same idea in other shifts

Asked 3× in all
  1. 8 Apr 2024, Shift 2 · Q47If MoM_o is the mass of isotope 512B{}^{12}_{5}\mathrm{B}, MPM_P and MnM_n are the masses of proton and neutron, then nuclear binding energy…EasySingle correct
  2. 9 Apr 2024, Shift 1 · Q47The energy equivalent of 11 g of substance is :EasySingle correct

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 108 of the 174 JEE Main shifts held from 2017 to 2026.