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Saturday, 31 October

JEE Main 2021 · PhysicsMultiple choiceDiagram basedMediumMulti-step

JEE Main 25 July 2021, Shift 2, Physics Q13

Question 13 of 90 in this shift, Physics question 13 of 30, Section A.

The given potentiometer has its wire of resistance 10 Ω\Omega. When the sliding contact is in the middle of the potentiometer wire, the potential drop across 2 Ω\Omega resistor is :

The figure, in words

Circuit: a 20 V cell connected across the ends A and B of a potentiometer wire (resistor drawn between A and B). A 2 ohm resistor is connected between end A and the sliding contact of the potentiometer wire (contact at the middle).
  1. (1)10 V
  2. (2)5 V
  3. (3)409\frac{40}{9} VOfficial answer
  4. (4)4011\frac{40}{11} V

Official answer

Option 3

NTA final key.

Chapter
Current Electricity
Topic
Kirchhoff's Laws
Idea tested
Voltage Divider Rule

Same idea in other shifts

Asked 4× in all
  1. 30 Jan 2024, Shift 1 · Q49A potential divider circuit is shown in figure. The output voltage V0V_0 is :EasyDiagram basedHas a figure
  2. 30 Jan 2024, Shift 1 · Q50Primary coil of a transformer is connected to 220 V ac. Primary and secondary turns of the transforms are 100 and 10 respectively.…EasyDiagram basedHas a figure
  3. 18 Mar 2021, Shift 1 · Q23The voltage across the 10 Ω\Omega resistor in the given circuit is xx volt. The value of 'x' to the nearest integer is __________.EasyNumerical valueHas a figure

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. This question needs a figure we do not reproduce; it is described in words above. Lumi analyses 108 of the 174 JEE Main shifts held from 2017 to 2026.