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Friday, 9 October

JEE Main 2021 · PhysicsMultiple choiceSingle correctMediumMulti-step

JEE Main 25 July 2021, Shift 1, Physics Q8

Question 8 of 90 in this shift, Physics question 8 of 30, Section A.

In the Young's double slit experiment, the distance between the slits varies in time as d(t)=d0+a0sin⁡ωtd(t)=d_0+a_0\sin\omega t ; where d0d_0, ω\omega and a0a_0 are constants. The difference between the largest fringe width and the smallest fringe width obtained over time is given as :
  1. (1)λDd02a0\frac{\lambda D}{d_0^2}a_0
  2. (2)2λD(d0)(d02−a02)\frac{2\lambda D(d_0)}{\left(d_0^2-a_0^2\right)}
  3. (3)λDd0+a0\frac{\lambda D}{d_0+a_0}
  4. (4)2λDa0(d02−a02)\frac{2\lambda Da_0}{\left(d_0^2-a_0^2\right)}Official answer

Official answer

Option 4

NTA final key.