JEE Main 2021 · ChemistryNumerical answerNumerical valueHardCalculation
JEE Main 25 July 2021, Shift 1, Chemistry Q58
Question 58 of 90 in this shift, Chemistry question 28 of 30, Section B.
Consider the cell at 25C
The fraction of total iron present as ion at the cell potential of 1.500 V is . The value of is _________. (Nearest integer)
(Given : V, V)
Official answer
24
NTA final key.
- Chapter
- Electrochemistry
- Topic
- Nernst Equation
- Idea tested
- Full Cell Nernst Equation