JEE Main 2021 · ChemistryMultiple choiceSingle correctHardMulti-step
JEE Main 25 July 2021, Shift 1, Chemistry Q44
Question 44 of 90 in this shift, Chemistry question 14 of 30, Section A.
[figure: 3,3-dimethylcyclopentanone (ketone C=O, gem-dimethyl on adjacent ring carbon) reacts with , NaOH to give 'P' (Major Product); then (i) , Filter (ii) Filtrate + HCl gives 'X']
Consider the given reaction, the product 'X' is :
The figure, in words
Reaction scheme starting from 3,3-dimethylcyclopentanone (as drawn: ketone with gem-dimethyl on the adjacent ring carbon) with CH3CHO/NaOH giving P, then I2/NaOH then HCl giving X.- (1)[figure: 2,2-dimethyl-cyclopentanone ring bearing -COOH on the other alpha carbon]Official answer
- (2)[figure: 2,2-dimethylcyclopentanone ring bearing -CH(OH)CH3 on the other alpha carbon]
- (3)[figure: 2,2-dimethylcyclopentanone ring bearing -C(=O)CH3 on the other alpha carbon]
- (4)[figure: cyclopentane ring with OH and CH2CHO on the same carbon, adjacent carbon bearing gem-dimethyl]
Official answer
Option 1
NTA final key.
- Topic
- Aldol and Cannizzaro
- Idea tested
- Cross-Aldol Condensation