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JEE Main 25 July 2021, Shift 1, Physics Q25

Question 25 of 90 in this shift, Physics question 25 of 30, Section B.

A particle of mass '

m

' is moving in time '

t

' on a trajectory given by

\vec{r}=10\alpha t^2\hat{i}+5\beta(t-5)\hat{j}

Where

\alpha

and

\beta

are dimensional constants. The angular momentum of the particle becomes the same as it was for

t=0

at time

t=

_________ seconds.

Official answer

NTA final key.

Same idea in other shifts