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JEE Main 2021 · PhysicsMultiple choiceSingle correctEasyApplication

JEE Main 25 July 2021, Shift 1, Physics Q19

Question 19 of 90 in this shift, Physics question 19 of 30, Section A.

The minimum and maximum distances of a planet revolving around the Sun are

x_1

and

x_2

. If the minimum speed of the planet on its trajectory is

v_0

then its maximum speed will be :

(1) $\frac{v_0x_2^2}{x_1^2}$
(2) $\frac{v_0x_1}{x_2}$
(3) $\frac{v_0x_2}{x_1}$ Official answer
(4) $\frac{v_0x_1^2}{x_2^2}$

Official answer

Option 3

NTA final key.

Chapter: Gravitation
Topic: Orbital Mechanics
Idea tested: Areal Velocity and Angular Momentum

Same idea in other shifts

Asked 2× in all

7 Apr 2025, Shift 2 · Q31Given below are two statements : one is labelled as Assertion (A) and the other is labelled as Reason (R). Assertion (A) : The radius…EasyAssertion–reason

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 42 of the 174 JEE Main shifts held from 2017 to 2026.