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Saturday, 31 October

JEE Main 2021 · MathsMultiple choiceSingle correctMediumApplication

JEE Main 25 February 2021, Shift 2, Maths Q67

Question 67 of 90 in this shift, Maths question 7 of 30, Section A.

The minimum value of f(x)=aax+a1−axf(x) = a^{a^x} + a^{1-a^x}, where a,x∈Ra, x \in \mathbf{R} and a>0a > 0, is equal to :
  1. (1)a+1a+1
  2. (2)a+1aa + \frac{1}{a}
  3. (3)2a2\sqrt{a}Official answer
  4. (4)2a2a

Official answer

Option 3

NTA final key.