JEE Main 2021 · ChemistryNumerical answerNumerical valueMediumCalculation

JEE Main 25 February 2021, Shift 2, Chemistry Q51

Question 51 of 90 in this shift, Chemistry question 21 of 30, Section B.

Consider titration of NaOH solution versus 1.25 M oxalic acid solution. At the end point following burette readings were obtained. (i) 4.5 mL (ii) 4.5 mL (iii) 4.4 mL (iv) 4.4 mL (v) 4.4 mL If the volume of oxalic acid taken was 10.0 mL then the molarity of the NaOH solution is ________ M. (Rounded-off to the nearest integer)

Official answer

NTA final key.

Chapter: Some Basic Concepts of Chemistry
Topic: Mole Concept
Idea tested: Normality and n-factor Calculation

Same idea in other shifts

Asked 5× in all

6 Apr 2023, Shift 2 · Q61The volume of 0.02 M aqueous HBr required to neutralize 10.0 mL of 0.01 M aqueous $\mathrm{Ba(OH)_2}$ is (Assume complete neutralization)EasySingle correct
27 Jul 2022, Shift 2 · Q81The normality of $\mathrm{H_2SO_4}$ in the solution obtained on mixing 100 mL of 0.1 M $\mathrm{H_2SO_4}$ with 50 mL of 0.1 M NaOH is…MediumNumerical value
25 Jun 2022, Shift 2 · Q90The neutralization occurs when 10 mL of 0.1M acid ‘A’ is allowed to react with 30 mL of 0.05 M base $\mathrm{M(OH)_2}$ . The basicity of…EasyNumerical value
3 Sep 2020, Shift 2 · Q49The volume (in mL) of 0.1 N $\mathrm{NaOH}$ required to neutralise 10 mL of 0.1 N phosphinic acid is __________.MediumNumerical value

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 108 of the 174 JEE Main shifts held from 2017 to 2026.