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Saturday, 31 October

JEE Main 2021 · ChemistryMultiple choiceSingle correctMediumRecall

JEE Main 25 February 2021, Shift 2, Chemistry Q46

Question 46 of 90 in this shift, Chemistry question 16 of 30, Section A.

What is ‘X’ in the given reaction ? [figure: CH2OH\mathrm{CH_2OH} over CH2OH\mathrm{CH_2OH} joined by a vertical line] + oxalic acid →210∘C\xrightarrow{210^\circ\mathrm{C}} X (major product)

The figure, in words

Reactant drawn as CH2OH (top) and CH2OH (bottom) joined by a vertical single line, followed by '+ oxalic acid', arrow labelled 210°C, product X (major product).
  1. (1)[figure: CHO\mathrm{CHO} over CHO\mathrm{CHO} joined by a vertical line]
  2. (2)[figure: CH2OH\mathrm{CH_2OH} over CHO\mathrm{CHO} joined by a vertical line]
  3. (3)[figure: CH2\mathrm{CH_2} double-bonded to CH2\mathrm{CH_2} (vertical)]Official answer
  4. (4)[figure: CH−OH\mathrm{CH{-}OH} double-bonded to CH2\mathrm{CH_2} (vertical)]

Official answer

Option 3

NTA final key.

Chapter
Alcohols, Phenols and Ethers
Topic
No close match in our taxonomy
Idea tested
No close match in our taxonomy

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. This question needs a figure we do not reproduce; it is described in words above. Lumi analyses 108 of the 174 JEE Main shifts held from 2017 to 2026.