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Saturday, 31 October

JEE Main 2021 · PhysicsNumerical answerNumerical valueMediumCalculation

JEE Main 25 February 2021, Shift 2, Physics Q26

Question 26 of 90 in this shift, Physics question 26 of 30, Section B.

Two small spheres each of mass 10 mg are suspended from a point by threads 0.5 m long. They are equally charged and repel each other to a distance of 0.20 m. The charge on each of the sphere is a21×10−8\frac{a}{21} \times 10^{-8} C. The value of ‘a’ will be ____________. [Given g = 10 ms−2^{-2}]

Official answer

20

NTA final key.

Chapter
Electric Charges and Fields
Topic
Coulomb's Law
Idea tested
Suspended Charge Mechanics

Same idea in other shifts

Asked 2× in all
  1. 3 Aug 2021, Shift 1 · Q10The diagram shows a scheme of two unequal masses, m1=2mm_1 = 2m and m2=mm_2 = m having unequal positive charge on them. They are suspended by…HardDiagram basedHas a figure

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 108 of the 174 JEE Main shifts held from 2017 to 2026.