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Saturday, 31 October

JEE Main 2021 · MathsMultiple choiceSingle correctMediumMulti-step

JEE Main 25 February 2021, Shift 1, Maths Q72

Question 72 of 90 in this shift, Maths question 12 of 30, Section A.

If the curves, x2a+y2b=1\frac{x^2}{a} + \frac{y^2}{b} = 1 and x2c+y2d=1\frac{x^2}{c} + \frac{y^2}{d} = 1 intersect each other at an angle of 90∘90^\circ, then which of the following relations is TRUE ?
  1. (1)a+b=c+da + b = c + d
  2. (2)a−b=c−da - b = c - dOfficial answer
  3. (3)ab=c+da+bab = \frac{c+d}{a+b}
  4. (4)a−c=b+da - c = b + d

Official answer

Option 2

NTA final key.

Same idea in other shifts

Asked 2× in all
  1. 25 Feb 2021, Shift 2 · Q85If the curves x=y4x = y^4 and xy=kxy = k cut at right angles, then (4k)6(4k)^6 is equal to ________.MediumNumerical value

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 108 of the 174 JEE Main shifts held from 2017 to 2026.