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JEE Main 25 February 2021, Shift 1, Physics Q30
Question 30 of 90 in this shift, Physics question 30 of 30, Section B.
In the given circuit of potentiometer, the potential difference E across AB (10 m length) is larger than and as well. For key (closed), the jockey is adjusted to touch the wire at point so that there is no deflection in the galvanometer. Now the first battery () is replaced by second battery () for working by making open and closed. The galvanometer gives then null deflection at . The value of is , where a = __________ .
The figure, in words
Potentiometer circuit: the potentiometer wire AB is drawn as a zig-zag of parallel segments running from A at the top to B at the bottom, with total length labelled 1 m (arrow at the bottom from B). A battery E, a key K and a rheostat Rh (zig-zag resistor with an arrow contact) are connected in series across A and B. At the top, two cells are drawn in parallel branches: E1 with key K1 (drawn with a filled dot, closed) and E2 with key K2 (drawn open); they connect to point A by a slanted line and, through a galvanometer G, to a jockey contact. Jockey position J1 is marked at a distance labelled 20 cm from A (arrow pointing up at the wire), and J2 is marked at a distance labelled 60 cm (arrow pointing up, joined by a dashed line to the galvanometer lead).Official answer
1
NTA final key.
- Chapter
- Current Electricity
- Topic
- Potentiometer
- Idea tested
- Comparing EMF of Two Cells