JEE Main 2021 · PhysicsMultiple choiceSingle correctEasyCalculation

JEE Main 25 February 2021, Shift 1, Physics Q3

Question 3 of 90 in this shift, Physics question 3 of 30, Section A.

If the time period of a two meter long simple pendulum is 2 s, the acceleration due to gravity at the place where pendulum is executing S.H.M. is :

(1) $16\ \mathrm{m/s^{2}}$
(2) $\pi^{2}\ \mathrm{ms^{-2}}$
(3) $9.8\ \mathrm{ms^{-2}}$
(4) $2\pi^{2}\ \mathrm{ms^{-2}}$ Official answer

Official answer

Option 4

NTA final key.

Chapter: Oscillations
Topic: Pendulums
Idea tested: Simple Pendulum Period

Same idea in other shifts

Asked 4× in all

28 Jul 2022, Shift 2 · Q6Assume there are two identical simple pendulum clocks. Clock - 1 is placed on the earth and Clock - 2 is placed on a space station located…MediumSingle correct
29 Jun 2022, Shift 2 · Q42The motion of a simple pendulum executing S.H.M. is represented by the following equation. $y = A\sin(\pi t + \phi)$ , where time is…EasySingle correct
22 Jul 2021, Shift 2 · Q20 $\mathrm{T_0}$ is the time period of a simple pendulum at a place. If the length of the pendulum is reduced to $\frac{1}{16}$ times of its…EasySingle correct

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 108 of the 174 JEE Main shifts held from 2017 to 2026.