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Saturday, 31 October

JEE Main 2021 · PhysicsMultiple choiceDiagram basedHardMulti-step

JEE Main 25 February 2021, Shift 1, Physics Q10

Question 10 of 90 in this shift, Physics question 10 of 30, Section A.

The current (ii) at time t=0 and t=∞\infty respectively for the given circuit is :

The figure, in words

A circuit: a battery E in a vertical middle branch with an arrow marked i pointing upward; the top-left arm has a 5 ohm resistor and the top-right arm a 5 ohm resistor, both meeting at the top of the battery branch; the bottom-left arm has a 1 ohm resistor and the bottom-right arm a 4 ohm resistor, both meeting at the bottom of the battery branch. The left and right ends of these arms are joined by vertical wires, and from the left and right sides an outer wire runs down and around to an inductor (coil) labelled L at the bottom.
  1. (1)18E55, 5E18\frac{18E}{55},\ \frac{5E}{18}
  2. (2)5E18, 18E55\frac{5E}{18},\ \frac{18E}{55}
  3. (3)10E33, 5E18\frac{10E}{33},\ \frac{5E}{18}
  4. (4)5E18, 10E33\frac{5E}{18},\ \frac{10E}{33}Official answer

Official answer

Option 4

NTA final key.

Chapter
Electromagnetic Induction
Topic
Inductance
Idea tested
Current Continuity in Inductors

Same idea in other shifts

Asked 2× in all
  1. 28 Jul 2022, Shift 2 · Q27For the given circuit the current through battery of 6 V just after closing the switch 'S' will be _______ A.MediumNumerical valueHas a figure

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. This question needs a figure we do not reproduce; it is described in words above. Lumi analyses 108 of the 174 JEE Main shifts held from 2017 to 2026.