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Saturday, 31 October

JEE Main 2021 · MathsMultiple choiceSingle correctEasyApplication

JEE Main 24 February 2021, Shift 2, Maths Q64

Question 64 of 90 in this shift, Maths question 4 of 30, Section A.

For which of the following curves, the line x+3y=23x+\sqrt{3}y=2\sqrt{3} is the tangent at the point (332,12)\left(\frac{3\sqrt{3}}{2},\frac{1}{2}\right) ?
  1. (1)x2+y2=7x^2+y^2=7
  2. (2)x2+9y2=9x^2+9y^2=9Official answer
  3. (3)y2=163xy^2=\frac{1}{6\sqrt{3}}x
  4. (4)2x2−18y2=92x^2-18y^2=9

Official answer

Option 2

NTA final key.