JEE Main 2021 (24 Feb, Shift 1) Physics Q1: The workdone…

Question

The workdone by a gas molecule in an isolated system is given by, $W = \alpha\beta^{2} e^{-\frac{x^{2}}{\alpha kT}}$, where $x$ is the displacement, $k$ is the Boltzmann constant and T is the temperature. $\alpha$ and $\beta$ are constants. Then the dimensions of $\beta$ will be :

Accepted Answer

Option 3: $[\mathrm{M\,L\,T^{-2}}]$

Answer

$[\mathrm{M^{2}\,L\,T^{2}}]$

Answer

$[\mathrm{M^{0}\,L\,T^{0}}]$

Answer

$[\mathrm{M\,L\,T^{-2}}]$

Answer

$[\mathrm{M\,L^{2}\,T^{-2}}]$

JEE Main 24 February 2021, Shift 1, Physics Q1