JEE Main 2021 · MathsNumerical answerNumerical valueMediumCalculation

JEE Main 31 August 2021, Shift 2, Maths Q87

Question 87 of 90 in this shift, Maths question 27 of 30, Section B.

If the line

y = \mathrm{m}x

bisects the area enclosed by the lines

x = 0

y = 0

x = \frac{3}{2}

and the curve

y = 1+4x-x^2

, then

12\,\mathrm{m}

is equal to ______________.

Official answer

NTA final key.

Chapter: Application of Integrals
Topic: Area Under Curves
Idea tested: Bisection of Bounded Areas

Same idea in other shifts

Asked 3× in all

8 Jan 2020, Shift 1 · Q61For $a>0$ , let the curves $C_1: y^2=ax$ and $C_2: x^2=ay$ intersect at origin O and a point P. Let the line $x=b$ ( $0<b<a$ ) intersect the…HardSingle correct
2 Sep 2020, Shift 2 · Q62Consider a region $R=\{(x,\ y)\in\mathbf{R}^2 : x^2\le y\le 2x\}$ . If a line $y=\alpha$ divides the area of region R into two equal parts,…MediumSingle correct

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 108 of the 174 JEE Main shifts held from 2017 to 2026.