JEE Main 2021 · ChemistryNumerical answerNumerical valueEasyCalculation

JEE Main 31 August 2021, Shift 2, Chemistry Q57

Question 57 of 90 in this shift, Chemistry question 27 of 30, Section B.

For the reaction A → B, the rate constant k (in

\mathrm{s^{-1}}

) is given by

\log_{10} k = 20.35 - \frac{(2.47 \times 10^3)}{T}

The energy of activation in

\mathrm{kJ\ mol^{-1}}

is __________. (Nearest integer) [Given : R = 8.314 J

\mathrm{K^{-1}\ mol^{-1}}

]

Official answer

NTA final key.

Chapter: Chemical Kinetics
Topic: Arrhenius Equation
Idea tested: Activation Energy Calculation

Same idea in other shifts

Asked 7× in all

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Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 108 of the 174 JEE Main shifts held from 2017 to 2026.