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Saturday, 31 October

JEE Main 2021 · PhysicsNumerical answerNumerical valueMediumCalculation

JEE Main 31 August 2021, Shift 1, Physics Q29

Question 29 of 90 in this shift, Physics question 29 of 30, Section B.

The electric field in an electromagnetic wave is given by E=(50 NC−1) sin⁡ω(t−x/c)E = (50\ \mathrm{NC^{-1}})\ \sin\omega(t - x/c) The energy contained in a cylinder of volume V is 5.5×10−125.5\times10^{-12} J. The value of V is __________ cm3^3. (given ϵ0=8.8×10−12 C2N−1m−2\epsilon_0 = 8.8\times10^{-12}\ \mathrm{C^2N^{-1}m^{-2}})

Official answer

500

NTA final key.

Chapter
Electromagnetic Waves
Topic
No close match in our taxonomy
Idea tested
No close match in our taxonomy

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 108 of the 174 JEE Main shifts held from 2017 to 2026.