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Saturday, 31 October

JEE Main 2021 · PhysicsNumerical answerNumerical valueEasyCalculation

JEE Main 31 August 2021, Shift 1, Physics Q22

Question 22 of 90 in this shift, Physics question 22 of 30, Section B.

A particle of mass 1 kg is hanging from a spring of force constant 100 Nm−1^{-1}. The mass is pulled slightly downward and released so that it executes free simple harmonic motion with time period T. The time when the kinetic energy and potential energy of the system will become equal, is Tx\frac{T}{x}. The value of xx is __________.

Official answer

8

NTA final key.