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Saturday, 31 October

JEE Main 2021 · PhysicsMultiple choiceSingle correctHardMulti-step

JEE Main 31 August 2021, Shift 1, Physics Q14

Question 14 of 90 in this shift, Physics question 14 of 30, Section A.

For an ideal gas the instantaneous change in pressure 'p' with volume 'v' is given by the equation dpdv=−ap\frac{dp}{dv} = -ap. If p=p0p = p_0 at v=0v = 0 is the given boundary condition, then the maximum temperature one mole of gas can attain is : (Here R is the gas constant)
  1. (1)0∘0^\circC
  2. (2)p0a e R\frac{p_0}{a\,e\,R}Official answer
  3. (3)ap0e R\frac{ap_0}{e\,R}
  4. (4)infinity

Official answer

Option 2

NTA final key.

Chapter
Thermodynamics
Topic
No close match in our taxonomy
Idea tested
No close match in our taxonomy

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 108 of the 174 JEE Main shifts held from 2017 to 2026.