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JEE Main 2021 · ChemistryMultiple choiceSingle correctMediumRecall

JEE Main 27 August 2021, Shift 2, Chemistry Q34

Question 34 of 90 in this shift, Chemistry question 4 of 30, Section A.

The oxide that gives

\mathrm{H_2O_2}

most readily on treatment with

\mathrm{H_2O}

is :

(1) $\mathrm{PbO_2}$
(2) $\mathrm{BaO_2 \cdot 8H_2O}$
(3) $\mathrm{Na_2O_2}$ Official answer
(4) $\mathrm{SnO_2}$

Official answer

Option 3

NTA final key.

Chapter: Hydrogen
Topic: Hydrogen and Hydrides
Idea tested: H2O2 Preparation from Barium Peroxide

Same idea in other shifts

Asked 2× in all

27 Jun 2022, Shift 1 · Q67Addition of $\mathrm{H_2SO_4}$ to $\mathrm{BaO_2}$ produces :EasySingle correct

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 108 of the 174 JEE Main shifts held from 2017 to 2026.