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JEE Main 27 August 2021, Shift 2, Physics Q25

Question 25 of 90 in this shift, Physics question 25 of 30, Section B.

A tuning fork is vibrating at 250 Hz. The length of the shortest closed organ pipe that will resonate with the tuning fork will be __________ cm. (Take speed of sound in air as 340

\mathrm{ms^{-1}}

)

Official answer

NTA final key.

Chapter: Waves
Topic: Resonance in Air Columns
Idea tested: Closed Organ Pipe Harmonics

Same idea in other shifts

Asked 4× in all

30 Jan 2024, Shift 1 · Q54In a closed organ pipe, the frequency of fundamental note is 30 Hz. A certain amount of water is now poured in the organ pipe so that the…HardNumerical value
12 Apr 2023, Shift 1 · Q55For a certain organ pipe, the first three resonance frequencies are in the ratio of 1:3:5 respectively. If the frequency of fifth harmonic…MediumNumerical value
28 Jun 2022, Shift 2 · Q57A tunning fork of frequency 340 Hz resonates in the fundamental mode with an air column of length 125 cm in a cylindrical tube closed at…MediumNumerical value

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 108 of the 174 JEE Main shifts held from 2017 to 2026.