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Saturday, 31 October

JEE Main 2021 · PhysicsMultiple choiceDiagram basedEasyDiagram reading

JEE Main 27 August 2021, Shift 2, Physics Q12

Question 12 of 90 in this shift, Physics question 12 of 30, Section A.

The colour coding on a carbon resistor is shown in the given figure. The resistance value of the given resistor is :

The figure, in words

A cylindrical resistor with a lead wire at each end and four coloured bands near one end; leader lines label the bands, from the band nearest the middle outward: Violet, Green, Red, Gold.
  1. (1)(5700±375) Ω(5700\pm375)\ \Omega
  2. (2)(7500±750) Ω(7500\pm750)\ \Omega
  3. (3)(5700±285) Ω(5700\pm285)\ \Omega
  4. (4)(7500±375) Ω(7500\pm375)\ \OmegaOfficial answer

Official answer

Option 4

NTA final key.

Chapter
Current Electricity
Topic
Ohm's Law and Resistance
Idea tested
Carbon Resistor Color Coding

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Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. This question needs a figure we do not reproduce; it is described in words above. Lumi analyses 108 of the 174 JEE Main shifts held from 2017 to 2026.