JEE Main 2021 · PhysicsMultiple choiceSingle correctMediumData or graph
JEE Main 27 August 2021, Shift 1, Physics Q9
Question 9 of 90 in this shift, Physics question 9 of 30, Section A.
The variation of displacement with time of a particle executing free simple harmonic motion is shown in the figure.
The potential energy U() versus time (t) plot of the particle is correctly shown in figure :
The figure, in words
Stem figure: x versus t sine curve starting at origin O, positive first half-cycle, crosses the t axis at A, negative half-cycle, crosses at B, positive half-cycle ending at C on the t axis.- (1)[figure: graph of U(x) versus t, sinusoidal curve starting at O going positive, crossing the t axis at A, negative between A and B, back to zero at B, positive again until C, dashed vertical lines at A, B, C]
- (2)[figure: graph of U(x) versus t, three positive arches (all above the t axis) touching the axis at A, B and C, dashed vertical lines at A, B, C]Official answer
- (3)[figure: graph of U(x) versus t, sinusoidal curve starting at O going negative, crossing the t axis at A, positive between A and B, back to zero at B, negative again until C, dashed vertical lines at A, B, C]
- (4)[figure: graph of U(x) versus t, three negative arches (all below the t axis) touching the axis at A, B and C, dashed vertical lines at A, B, C]
Official answer
Option 2
NTA final key.
- Chapter
- Oscillations
- Topic
- Energy in SHM
- Idea tested
- Energy-Time Graphs in SHM