JEE Main 2021 · ChemistryNumerical answerNumerical valueHardMulti-step
JEE Main 27 August 2021, Shift 1, Chemistry Q53
Question 53 of 90 in this shift, Chemistry question 23 of 30, Section B.
1 kg of 0.75 molal aqueous solution of sucrose can be cooled up to before freezing. The amount of ice (in g) that will be separated out is __________. (Nearest integer)
[Given : () = 1.86 K kg ]
Official answer
518
NTA final key.
- Chapter
- Solutions
- Idea tested
- Freezing Point Depression