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Saturday, 31 October

JEE Main 2021 · ChemistryMultiple choiceSingle correctMediumRecall

JEE Main 27 August 2021, Shift 1, Chemistry Q50

Question 50 of 90 in this shift, Chemistry question 20 of 30, Section A.

Acidic ferric chloride solution on treatment with excess of potassium ferrocyanide gives a Prussian blue coloured colloidal species. It is :
  1. (1)Fe4[Fe(CN)6]3\mathrm{Fe_4[Fe(CN)_6]_3}
  2. (2)HFe[Fe(CN)6]\mathrm{HFe[Fe(CN)_6]}
  3. (3)KFe[Fe(CN)6]\mathrm{KFe[Fe(CN)_6]}Official answer
  4. (4)K5Fe[Fe(CN)6]2\mathrm{K_5Fe[Fe(CN)_6]_2}

Official answer

Option 3

NTA final key.

Topic
No close match in our taxonomy
Idea tested
No close match in our taxonomy

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 108 of the 174 JEE Main shifts held from 2017 to 2026.