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Saturday, 31 October

JEE Main 2021 · PhysicsMultiple choiceSingle correctEasyCalculation

JEE Main 27 August 2021, Shift 1, Physics Q15

Question 15 of 90 in this shift, Physics question 15 of 30, Section A.

Electric field in a plane electromagnetic wave is given by E=50 sin⁡(500x−10×1010t)\mathrm{E}=50\ \sin(500x-10\times10^{10}\mathrm{t}) V/m The velocity of electromagnetic wave in this medium is : (Given C == speed of light in vacuum)
  1. (1)23\frac{2}{3}COfficial answer
  2. (2)C
  3. (3)32\frac{3}{2}C
  4. (4)C2\frac{\mathrm{C}}{2}

Official answer

Option 1

NTA final key.

Chapter
Electromagnetic Waves
Topic
No close match in our taxonomy
Idea tested
No close match in our taxonomy

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 108 of the 174 JEE Main shifts held from 2017 to 2026.