Learn

Saturday, 31 October

JEE Main 2021 · PhysicsMultiple choiceSingle correctMediumCalculation

JEE Main 27 August 2021, Shift 1, Physics Q1

Question 1 of 90 in this shift, Physics question 1 of 30, Section A.

In Millikan’s oil drop experiment, what is viscous force acting on an uncharged drop of radius 2.0×10−52.0\times10^{-5} m and density 1.2×1031.2\times10^{3} kgm−3^{-3} ? Take viscosity of liquid =1.8×10−5=1.8\times10^{-5} Nsm−2^{-2}. (Neglect buoyancy due to air).
  1. (1)5.8×10−105.8\times10^{-10} N
  2. (2)1.8×10−101.8\times10^{-10} N
  3. (3)3.8×10−113.8\times10^{-11} N
  4. (4)3.9×10−103.9\times10^{-10} NOfficial answer

Official answer

Option 4

NTA final key.

Idea tested
Stokes' Law