JEE Main 2021 · PhysicsMultiple choiceSingle correctMediumMulti-step
JEE Main 26 August 2021, Shift 1, Physics Q9
Question 9 of 90 in this shift, Physics question 9 of 30, Section A.
An inductor coil stores 64 J of magnetic field energy and dissipates energy at the rate of 640 W when a current of 8 A is passed through it. If this coil is joined across an ideal battery, find the time constant of the circuit in seconds :
- (1)0.2Official answer
- (2)0.4
- (3)0.8
- (4)0.125
Official answer
Option 1
NTA final key.
- Chapter
- Electromagnetic Induction
- Topic
- Inductance
- Idea tested
- Energy Stored in Inductors