JEE Main 2021 · ChemistryNumerical answerNumerical valueMediumApplication

JEE Main 26 August 2021, Shift 1, Chemistry Q58

Question 58 of 90 in this shift, Chemistry question 28 of 30, Section B.

The number of 4

f

electrons in the ground state electronic configuration of

\mathrm{Gd^{2+}}

is __________. [Atomic number of Gd = 64]

Official answer

NTA final key.

Chapter: The d- and f-Block Elements
Topic: f-Block Elements
Idea tested: Anomalous Electronic Configuration of Gadolinium

Same topic in other shifts

All f-Block Elements questions

4 Apr 2026, Shift 1 · Q60The correct statements among the following are, A. Mo(VI) and W(VI) are less stable than Cr(VI). B. $\mathrm{Ce^{4+}}$ and…HardOther
4 Apr 2026, Shift 2 · Q59Pairs of elements with the same number of electrons in their respective 4f orbital are [Atomic number: Eu-63, Gd-64, Dy-66, Ho-67, Tm-69,…MediumOther
6 Apr 2024, Shift 1 · Q69The number of element from the following that do not belong to lanthanoids is Eu, Cm, Er, Tb, Yb and LuEasySingle correct
9 Apr 2024, Shift 1 · Q87Number of colourless lanthanoid ions among the following is ________. $\mathrm{Eu^{3+}, Lu^{3+}, Nd^{3+}, La^{3+}, Sm^{3+}}$ MediumNumerical value
27 Jan 2024, Shift 1 · Q68The electronic configuration for Neodymium is : [Atomic Number for Neodymium 60]EasySingle correct
30 Jan 2024, Shift 1 · Q67Diamagnetic Lanthanoid ions are :MediumSingle correct

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 108 of the 174 JEE Main shifts held from 2017 to 2026.