JEE Main 2021 · PhysicsMultiple choiceDiagram basedMediumMulti-step
JEE Main 26 August 2021, Shift 1, Physics Q12
Question 12 of 90 in this shift, Physics question 12 of 30, Section A.
In the given figure, the emf of the cell is 2.2 V and if internal resistance is 0.6 . Calculate the power dissipated in the whole circuit :
The figure, in words
Rectangular network with terminals A (left) and B (right) joined to a cell labelled 2.2 V, r=0.6 . Top side resistor 4 , bottom side resistor 8 . Four more resistors run from the four corners towards the centre: top-left 4 , top-right 4 , bottom-left 2 , bottom-right 8 . At the centre the two diagonal lines cross, one drawn with a small semicircular hump over the other.- (1)2.2 WOfficial answer
- (2)4.4 W
- (3)0.65 W
- (4)1.32 W
Official answer
Option 1
NTA final key.
- Chapter
- Current Electricity
- Topic
- Kirchhoff's Laws
- Idea tested
- Circuit Symmetry Analysis