JEE Main 2021 · PhysicsNumerical answerNumerical valueMediumMulti-step

JEE Main 4 August 2021, Shift 2, Physics Q22

Question 22 of 90 in this shift, Physics question 22 of 30, Section B.

Two heaters X and Y are connected is parallel across the supply of V volts. Heater X generates 500 kCal of heat in 20 minutes while Y generates 1000 kCal in 10 minutes. The resistance of heater X is

10\Omega

. If these heaters are connected in series across the same voltage, then the heat produced in 5 minutes will be _________ kCal.

Official answer

100

NTA final key.

Chapter: Current Electricity
Topic: Ohm's Law and Resistance
Idea tested: Power Dissipation Ratios in Series vs Parallel

Same idea in other shifts

Asked 5× in all

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Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 108 of the 174 JEE Main shifts held from 2017 to 2026.