JEE Main 2021 · MathsMultiple choiceSingle correctMediumMulti-step

JEE Main 4 August 2021, Shift 1, Maths Q70

Question 70 of 90 in this shift, Maths question 10 of 30, Section A.

The equation of the tangent to the curve

y=\int_{x^2}^{x^3}\frac{dt}{\sqrt{1+t^2}}

at the point whose abscissa is 1, is

(1) $x+\sqrt{2}y-1=0$
(2) $\sqrt{3}x-y-\sqrt{3}=0$
(3) $x-y-1=0$
(4) $x-\sqrt{2}y-1=0$ Official answer

Official answer

Option 4

NTA final key.

Chapter: Application of Derivatives
Topic: Tangents and Normals
Idea tested: Equation of Tangent

Same idea in other shifts

Asked 3× in all

6 Apr 2023, Shift 1 · Q28Let the tangent to the curve $x^2+2x-4y+9=0$ at the point $P(1,3)$ on it meet the $y$ -axis at A. Let the line passing through P and…MediumNumerical value
24 Feb 2021, Shift 2 · Q70If the curve $y=ax^2+bx+c$ , $x\in$ R, passes through the point (1, 2) and the tangent line to this curve at origin is $y=x$ , then the…EasySingle correct

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 108 of the 174 JEE Main shifts held from 2017 to 2026.