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Saturday, 31 October

JEE Main 2021 · PhysicsMultiple choiceSingle correctMediumMulti-step

JEE Main 4 August 2021, Shift 1, Physics Q14

Question 14 of 90 in this shift, Physics question 14 of 30, Section A.

The magnetic field in any region is given by B⃗=B0(2+xa)k^\vec{B}=B_0\left(2+\frac{x}{a}\right)\hat{k}. A square loop of edge length ‘l’ is placed with its edge along x and y axis. The loop is moved with a constant velocity v‾=v0i^\overline{v}=v_0\hat{i}. The emf induced in the loop will be -
  1. (1)zero
  2. (2)v0B0ℓv_0B_0\ell
  3. (3)v0B0ℓ2av_0B_0\frac{\ell^2}{a}Official answer
  4. (4)v0B0ℓ22av_0B_0\frac{\ell^2}{2a}

Official answer

Option 3

NTA final key.