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Friday, 9 October

JEE Main 2021 · ChemistryNumerical answerNumerical valueHardMulti-step

JEE Main 3 August 2021, Shift 2, Chemistry Q54

Question 54 of 90 in this shift, Chemistry question 24 of 30, Section B.

The work done by an ideal monoatomic gas when it is taken along the path ABCD as shown in the figure is xP0V0xP_0V_0. The value of (−x)(-x) is ‾\underline{\hspace{2em}}. (Nearest integer) [ln 2 = 0.69]

The figure, in words

P-V diagram: A at (V0, P0) and B at (2V0, P0) joined by a horizontal line (isobaric); B to C is a curve labelled 'Reversible, isothermal' down to C at volume 4V0; C to D is a horizontal line at the lower pressure back to D at volume 2V0 (D lies below B). Axes labelled P (with P0 marked) and V (V0, 2V0, 4V0 marked).

Official answer

1

NTA final key.

Chapter
Thermodynamics (Chemistry)
Topic
No close match in our taxonomy
Idea tested
No close match in our taxonomy

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. This question needs a figure we do not reproduce; it is described in words above. Lumi analyses 42 of the 174 JEE Main shifts held from 2017 to 2026.