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Friday, 9 October

JEE Main 2021 · PhysicsNumerical answerNumerical valueMediumCalculation

JEE Main 3 August 2021, Shift 2, Physics Q26

Question 26 of 90 in this shift, Physics question 26 of 30, Section B.

Two particles of equal mass 'm' go round a circle of radius RR under the action of their mutual gravitational attraction. The speed of each particle is 1x⋅GmR\sqrt{\frac{1}{x}\cdot\frac{Gm}{R}} where xx is ‾\underline{\hspace{2em}}.

Official answer

4

NTA final key.