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Saturday, 31 October

JEE Main 2021 · MathsNumerical answerNumerical valueMediumCalculation

JEE Main 3 August 2021, Shift 1, Maths Q81

Question 81 of 90 in this shift, Maths question 21 of 30, Section B.

If x2−x+1=0x^2 - x + 1 = 0, then the value of ∑n=15(xn+1xn)2\sum_{n=1}^{5}\left(x^n + \frac{1}{x^n}\right)^2 is ________.

Official answer

8

NTA final key.

Same idea in other shifts

Asked 2× in all
  1. 4 Apr 2025, Shift 2 · Q21If α\alpha is a root of the equation x2+x+1=0x^2+x+1=0 and ∑k=1n(αk+1αk)2=20\sum_{k=1}^{n}\left(\alpha^k+\frac{1}{\alpha^k}\right)^2=20, then n is equal to…MediumNumerical value

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 108 of the 174 JEE Main shifts held from 2017 to 2026.