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Saturday, 31 October

JEE Main 2021 · MathsMultiple choiceSingle correctMediumCalculation

JEE Main 3 August 2021, Shift 1, Maths Q69

Question 69 of 90 in this shift, Maths question 9 of 30, Section A.

If ∫4x+13x2+5x+6 dx=Ax2+5x+6+Blog⁡e∣(x+52)+x2+5x+6∣+C\int \frac{4x + 13}{\sqrt{x^2 + 5x + 6}}\,dx = A\sqrt{x^2 + 5x + 6} + B\log_e \left|\left(x + \frac{5}{2}\right) + \sqrt{x^2 + 5x + 6}\right| + C (C is a constant of integration), then the ordered pair (A, B) is equal to
  1. (1)(3,4)(3, 4)
  2. (2)(4,32)\left(4, \frac{3}{2}\right)
  3. (3)(2,3)(2, 3)
  4. (4)(4,3)(4, 3)Official answer

Official answer

Option 4

NTA final key.

Chapter
Integrals