Learn

Friday, 9 October

JEE Main 2020 · MathsNumerical answerNumerical valueMediumCalculation

JEE Main 6 September 2020, Shift 2, Maths Q75

Question 75 of 75 in this shift, Maths question 25 of 25.

Consider the data on xx taking the values 0,2,4,8,…,2n0, 2, 4, 8, \ldots, 2^n with frequencies nC0,nC1,nC2,…,nCn{}^nC_0, {}^nC_1, {}^nC_2, \ldots, {}^nC_n respectively. If the mean of this data is 7282n\frac{728}{2^n}, then n is equal to ________.

Official answer

6.00

NTA final key (Sep 2020).

Chapter
Statistics