JEE Main 2020 (6 Sep, Shift 2) Maths Q60: Maxima and Minima

Question

The set of all real values of $\lambda$ for which the function $f(x)=(1-\cos^2 x)\cdot(\lambda+\sin x)$, $x\in\left(-\frac{\pi}{2},\frac{\pi}{2}\right)$, has exactly one maxima and exactly one minima, is :

Accepted Answer

Option 3: $\left(-\frac{3}{2},\frac{3}{2}\right)-\{0\}$

Answer

$\left(-\frac{1}{2},\frac{1}{2}\right)-\{0\}$

Answer

$\left(-\frac{1}{2},\frac{1}{2}\right)$

Answer

$\left(-\frac{3}{2},\frac{3}{2}\right)-\{0\}$

Answer

$\left(-\frac{3}{2},\frac{3}{2}\right)$

JEE Main 6 September 2020, Shift 2, Maths Q60

Same idea in other shifts