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Friday, 9 October

JEE Main 2020 · MathsMultiple choiceSingle correctMediumMulti-step

JEE Main 6 September 2020, Shift 2, Maths Q56

Question 56 of 75 in this shift, Maths question 6 of 25.

The common difference of the A.P. b1,b2,…,bmb_1, b_2, \ldots, b_m is 2 more than the common difference of A.P. a1,a2,…,ana_1, a_2, \ldots, a_n. If a40=−159a_{40}=-159, a100=−399a_{100}=-399 and b100=a70b_{100}=a_{70}, then b1b_1 is equal to :
  1. (1)8181
  2. (2)−81-81Official answer
  3. (3)127127
  4. (4)−127-127

Official answer

Option 2

NTA final key (Sep 2020).

Idea tested
AP General Term