JEE Main 2020 (6 Sep, Shift 2) Physics Q1: A student…

Question

A student measuring the diameter of a pencil of circular cross-section with the help of a vernier scale records the following four readings 5.50 mm, 5.55 mm, 5.45 mm ; 5.65 mm. The average of these four readings is 5.5375 mm and the standard deviation of the data is 0.07395 mm. The average diameter of the pencil should therefore be recorded as :

(1) $(5.5375 \pm 0.0740)$ mm
(2) $(5.538 \pm 0.074)$ mm
(3) $(5.54 \pm 0.07)$ mmOfficial answer
(4) $(5.5375 \pm 0.0739)$ mm

Official answer

Option 3

NTA final key (Sep 2020).

Accepted Answer

Option 3: $(5.54 \pm 0.07)$ mm

Answer

$(5.5375 \pm 0.0740)$ mm

Answer

$(5.538 \pm 0.074)$ mm

Answer

$(5.54 \pm 0.07)$ mm

Answer

$(5.5375 \pm 0.0739)$ mm

JEE Main 6 September 2020, Shift 2, Physics Q1